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Palak Srivastava

Subject: Maths, asked on 9/5/18

Find the value equal to cos(cos^-1 cos(8pi/7) + tan^-1 tan (8pi/7))

Palak Srivastava

Subject: Maths, asked on 9/5/18

Solve this :

$Q . T h e v a l u e o f s e c [\sin^{- 1} [- \sin \frac{50 π}{9}] + \cos^{- 1} \cos [- \frac{31 π}{9}]] i s e q u a l t o -$

Sudhanshu Singh

Subject: Maths, asked on 8/5/18

Solvr this:

15. ( EXEMPLAR) Find the value of $\tan^{- 1} (\tan \frac{5 π}{6}) + \cos^{- 1} (\frac{13 π}{6}) .$

Sudhanshu Singh

Subject: Maths, asked on 8/5/18

Solve this and plzz don't give any link.
Q.14. Let a, b, c be positive real numbers. Let $θ = \tan^{- 1} \sqrt{\frac{a (a + b + c)}{b c}} + \tan^{- 1} \sqrt{\frac{b (a + b + c)}{c a}} + \tan^{- 1} \sqrt{\frac{c (a + b + c)}{a b}}$ . Then $\tan θ =__________$

Garvit Yadav

Subject: Maths, asked on 6/5/18

how to solve sin inverse 1+cos inverse 1=pie /2

Palak Srivastava

Subject: Maths, asked on 5/5/18

If $θ = \tan^{- 1} (2 \tan^{2} θ) - \frac{1}{2} \sin^{- 1} (\frac{3 \sin 2 θ}{5 + 4 \cos 2 θ})$ then find the sum of all the possible values of tan θ.

Bhavishya Raj

Subject: Maths, asked on 4/5/18

Please solve it!
Q.8. $\tan^{- 1} (\frac{\cos x - \sin x}{\cos x + \sin x}), 0 < x < π$

Bhavishya Raj

Subject: Maths, asked on 3/5/18

What is value of cosec 90

Samiksha Jain

Subject: Maths, asked on 3/5/18

1/cos0cos1 +1/cos1cos2 +......+1/cos88cos89 is equal to

1. sin1/cos²1 2.cos1/sin²1 3.sin²1/cos²1 34.cos²1/sin1

Vivek Kumar

Subject: Maths, asked on 2/5/18

Plzz explain the domain and range of inverse funtion of cot, sec and cosec with appropriate graphs

Bhavya Jain

Subject: Maths, asked on 1/5/18

Is there an easy mwt od to find solution to the following Relation and function question?

Sanjukta Biswas

Subject: Maths, asked on 30/4/18

Q. Prove the following
(iii) $\tan^{- 1} \frac{2}{3} = \frac{1}{2} \tan^{- 1} \frac{12}{5}$

Sanjukta Biswas

Subject: Maths, asked on 30/4/18

Q. Prove the following
(ii) $\tan^{- 1} \frac{1}{4} + \tan^{- 1} \frac{2}{9} = \frac{1}{2} \cos^{- 1} \frac{3}{5} = \frac{1}{2} \sin^{- 1} (\frac{4}{5})$

Alok Singh

Subject: Maths, asked on 28/4/18

Solve this:
Q. Prove that $\sin^{2} \{\cos^{- 1} [\tan (\sin^{- 1} x)]\} = \frac{1 - 2 x^{2}}{1 - x^{2}}$

Palak Srivastava

Subject: Maths, asked on 28/4/18

Solve the equation 2tan^-1 (2x+1)= cos^-1 x

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