Given the polynomial p(x)= x3-11x2+17x-6 . If p(x)= (x-2) q(x) + r , Then what is the valur of r and q(x) . Write p(x) as the products of three first degree polynomials .
The expression p(x) = 2x3+ax2-bx-2 leaves the remainder 7 when divided by (2x-3) and (x+2) is a factor of the expression . calculate the values of a and b ? ( need the stept too ! ) :)
Benny factorised a second degree polynomial ang got (x+2) , (x-3) as factors. But later he found that he was mistakenly taken the opposite sign of coefficient of x . What are the factors of the actual polynomial ?
Urgent...:'( ..Equation of getting one solution , two solution and no solution ( 3 examples each ) .
Check whether first is a factor of second .
x+1 , x3 -1
we will get ax3 + (b+a)x2 + (c+b)x + (c+d) and after this step how we are getting the value of 'a' as 1 , 'b' as -1 and 'c' as 1
Given the polynomial p(x)= x3-11x2+17x-6 . If p(x)= (x-2) q(x) + r , Then what is the valur of r and q(x) . Write p(x) as the products of three first degree polynomials .
The expression p(x) = 2x3+ax2-bx-2 leaves the remainder 7 when divided by (2x-3) and (x+2) is a factor of the expression . calculate the values of a and b ? ( need the stept too ! ) :)
Benny factorised a second degree polynomial ang got (x+2) , (x-3) as factors. But later he found that he was mistakenly taken the opposite sign of coefficient of x . What are the factors of the actual polynomial ?
Urgent...:'( ..Equation of getting one solution , two solution and no solution ( 3 examples each ) .
Check whether first is a factor of second .
x+1 , x3 -1
we will get ax3 + (b+a)x2 + (c+b)x + (c+d) and after this step how we are getting the value of 'a' as 1 , 'b' as -1 and 'c' as 1
p(x)= x? + 4x? + ax + 5 by (x+2) are same number. What is the number a ?