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Abhishek Mishra
Subject: Math
, asked on 24/5/18
A relation (phi) from C to R is defined by x(phi)y this implies that mod x=y which of the following is correct?
2+3i (phi) 13
3 (phi)-3
i (phi)1
1+i (phi)2
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Q). The solution of Logarithmic inequality
$\mathrm{log}\sqrt{\left(2x-1\right)}+\mathrm{log}\sqrt{\left(x-9\right)}>1$
(A) (0, 13)
(B) (13,
$\infty $
)
(C) (- 13, 13)
(D) None of these
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Pls solve and answer the question in detail.
Q. If x, y and z are real then the possible value of the expression
${x}^{2}+4{y}^{2}+9{z}^{2}-6yz-3zx-2xy$
may be.
(A) Non negative
(B) negative
(C) zero
(D) Any real no.
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
pls solve and answer the question in detail.
If log
_{4}
5 = x and log
_{5}
6 = y, then
(A) log
_{4}
6 = xy (B) log
_{6}
4 = xy (C) log
_{3}
2 =
$\frac{1}{2xy-1}$
(D) log
_{2}
3 =
$\frac{1}{2xy-1}$
Answer
3
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Pls solve and answer the question in detail.
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Pls solve and answer the question in detail.
Q.
$\left|\frac{\mathrm{x}+7}{\mathrm{x}}\right|+\left|\mathrm{x}+7\right|=\frac{{\left|\mathrm{x}+7\right|}^{2}}{\left|\mathrm{x}\right|}$
than which of the statement is correct
(A) Only one negative integer satisfy the equation
(B) All positive real no satisfy the given equation
(C) The solution set is R
(D) All positive integer are only the solution of equation
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Q). If
$\frac{1}{{\mathrm{log}}_{3}\mathrm{\pi}}+\frac{1}{{\displaystyle {\mathrm{log}}_{4}}{\displaystyle \mathrm{\pi}}}>k$
than the value of k is where k is any integer.
(A) 1
(B) 2
(C) 3
(D) 4
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Q). Number of possible value of pair (x, y) such that
$x+y+\frac{x}{y}=\frac{1}{2},\left(x+y\right)\frac{x}{y}=-\frac{1}{2}$
(A) 1
(B) 2
(C) 0
(D) None of these
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Pls solve and answer the question in detail.:
3. The ordered pair (x, y) satisfying the equation x
^{2}
=1+6log
_{4}
y and y
^{2}
=2
^{x}
y+2
^{2x+1}
are (x
_{1}
, y
_{1}
) and (x
_{2}
, y
_{2}
), then find the value of
${\mathrm{log}}_{2}\left|{\mathrm{x}}_{1}{\mathrm{x}}_{2}{\mathrm{y}}_{1}{\mathrm{y}}_{2}\right|=?$
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Pls solve and answer the question in detail.
Q. If x, y satisfy the equation
${y}^{x}={x}^{y}$
and x = 2 y then
$\frac{{x}^{2}+{y}^{2}}{5}=?$
Answer
2
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Pls solve the question and answer with detail.:
4. The number of negative integral value of x satisfying the inequality
${\mathrm{log}}_{\left(\mathrm{x}+\frac{5}{2}\right)}{\left(\frac{\mathrm{x}-5}{2\mathrm{x}-3}\right)}^{2}<0\mathrm{is}.$
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
$If{\mathrm{log}}_{10}\left|{x}^{3}+{y}^{3}\right|-{\mathrm{log}}_{10}\left|{x}^{2}-xy+{y}^{2}\right|+{\mathrm{log}}_{10}\left|{x}^{3}+{y}^{3}\right|-{\mathrm{log}}_{10}\left|{x}^{2}-xy+{y}^{2}\right|={\mathrm{log}}_{10}221wherex,yareintegers,then\phantom{\rule{0ex}{0ex}}Ifx=111thenycanbe\phantom{\rule{0ex}{0ex}}A)\pm 111B)\pm 2C)\pm 110D)\pm 109\phantom{\rule{0ex}{0ex}}Ify=2thenxcanbe\phantom{\rule{0ex}{0ex}}A)\pm 111B)\pm 15C)\pm 2D)\pm 110\phantom{\rule{0ex}{0ex}}$
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Please solve and answer with detail.
Answer
1
Kshitiz Anand
Subject: Math
, asked on 23/5/18
Qno 11 plz provide a detailed solution
Answer
1
Jeevesh Banchhor
Subject: Math
, asked on 23/5/18
Please solve all the questions with detailed answers within 10 hours.
Answer
1
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2
3
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Next
What are you looking for?

(A) (0, 13)

(B) (13, $\infty $)

(C) (- 13, 13)

(D) None of these

Q. If x, y and z are real then the possible value of the expression ${x}^{2}+4{y}^{2}+9{z}^{2}-6yz-3zx-2xy$ may be.

(A) Non negative

(B) negative

(C) zero

(D) Any real no.

If log

_{4}5 = x and log_{5}6 = y, then(A) log

_{4}6 = xy (B) log_{6}4 = xy (C) log_{3}2 = $\frac{1}{2xy-1}$ (D) log_{2}3 = $\frac{1}{2xy-1}$Q. $\left|\frac{\mathrm{x}+7}{\mathrm{x}}\right|+\left|\mathrm{x}+7\right|=\frac{{\left|\mathrm{x}+7\right|}^{2}}{\left|\mathrm{x}\right|}$ than which of the statement is correct

(A) Only one negative integer satisfy the equation

(B) All positive real no satisfy the given equation

(C) The solution set is R

(D) All positive integer are only the solution of equation

(A) 1

(B) 2

(C) 3

(D) 4

(A) 1

(B) 2

(C) 0

(D) None of these

3. The ordered pair (x, y) satisfying the equation x

^{2}=1+6log_{4}y and y^{2}=2^{x}y+2^{2x+1}are (x_{1}, y_{1}) and (x_{2}, y_{2}), then find the value of ${\mathrm{log}}_{2}\left|{\mathrm{x}}_{1}{\mathrm{x}}_{2}{\mathrm{y}}_{1}{\mathrm{y}}_{2}\right|=?$Q. If x, y satisfy the equation ${y}^{x}={x}^{y}$ and x = 2 y then $\frac{{x}^{2}+{y}^{2}}{5}=?$

4. The number of negative integral value of x satisfying the inequality ${\mathrm{log}}_{\left(\mathrm{x}+\frac{5}{2}\right)}{\left(\frac{\mathrm{x}-5}{2\mathrm{x}-3}\right)}^{2}<0\mathrm{is}.$