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Muhammad Khalid Aziz
Subject: Chemistry
, asked on 22/10/15
why is physical equilibrium called dynamic equilibrium?
Answer
1
Tejal Gugliya
Subject: Chemistry
, asked on 19/3/15
state LE-CHATERLIER principle. how it explain effect of change in concentration on composition of equilibrium mixture ?
Answer
1
Anushka .
Subject: Chemistry
, asked on 17/9/17
Three moles of N
2
react with 2 mol of O
2
in a two-litre container to form one mole of NO. What will be the number of moles of O
2
per litre at equilibrium?
(1) 0.75 (2) 1.50 (3) 1.25 (4) None of the above
Answer
1
Anushka .
Subject: Chemistry
, asked on 15/9/17
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Hrishikesh
Subject: Chemistry
, asked on 9/9/17
please solve 6.5 and 6.4 sum... Given the reaction : A 63 mole Of A and one mole of B 1.0 litre vessel. After established, 0.4 mole of C is present in 64 The equilibrium constant for the Of co-a reaction, + H20 (g) CO at a certain temperature is 2.2. Initially one mole 6•10 of CO and one mole of H20 are placed in a 2.0L acid is container. What are the concentrations of all the substances when the reaction reaches equilibrium? ([C02] = [H2] = 0.2986M, = = (1.83 ) 6.12 0.2014M).
6.5 Calculate Kp for the reaction, c(s) + H20 (g) CO(g) + H2(g) 6.13 at 990 K if the equilibrium concentrations are as 6.14 ca follows : [H20] = 1.10M, [COI = = 0.2M, R = 0.08206 L atm mor . 6.15 (Hint : First calculate Kc) (Kp 2.954) 6.6 The equilibrium constant Kc for the reaction —-—-.y 2NH3 (g) is 0.286 at 5000C. Calculate Kc and Kp for the 6.1t
Answer
1
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What are you looking for?
(1) 0.75 (2) 1.50 (3) 1.25 (4) None of the above
6.5 Calculate Kp for the reaction, c(s) + H20 (g) CO(g) + H2(g) 6.13 at 990 K if the equilibrium concentrations are as 6.14 ca follows : [H20] = 1.10M, [COI = = 0.2M, R = 0.08206 L atm mor . 6.15 (Hint : First calculate Kc) (Kp 2.954) 6.6 The equilibrium constant Kc for the reaction —-—-.y 2NH3 (g) is 0.286 at 5000C. Calculate Kc and Kp for the 6.1t