form a quadratic polynomial whose zeroes are 4 and 6

Smaller diagonal QS of a parallelogram PQRS is perpendicular to the sides PQ and RS. prove that PR^{2}-QS^{2}=4PQ^{2}

A number of the form xxyy when divided by 11 gives a number which is again divisible by 11.If x - y = 1 , find the number.

if the roots of a quadratic equation x2 + px + 16=0, are equal, then the value of p is?

If α and β are the zeros of the quadratic polynomial f(x) = x2 - px + q, prove that a2/b2 + b2/a2 = p4/q2 - 4p2/q + 2

Given thatαandβare the zeroes of the quadratic polynomialf(x) =x^{2}–px+q

how to calculate mode if two classes have same and highest frequency (bimodal) ?

form a quadratic polynomial whose zeroes are 4 and 6

Smaller diagonal QS of a parallelogram PQRS is perpendicular to the sides PQ and RS. prove that PR

^{2}-QS^{2}=4PQ^{2}A number of the form xxyy when divided by 11 gives a number which is again divisible by 11.If x - y = 1 , find the number.

(a) German

(b) Swiss

(c) French

(d) American

^{2}–p(x+1) - c such that (α+1)(β+1) = 0, then find the value of c.if the roots of a quadratic equation x2 + px + 16=0, are equal, then the value of p is?

write down the decimal expansion of the following rational numbers.

1) 241 / 2 cube 5 square

2) 25/ 1600

3) 19 / 256

4) 9 / 30

5) 133/ 2 cube 5 to power of 4

please revert back with answers & no links .

If α and β are the zeros of the quadratic polynomial f(x) = x2 - px + q, prove that a2/b2 + b2/a2 = p4/q2 - 4p2/q + 2Given that

αandβare the zeroes of the quadratic polynomialf(x) =x^{2}–px+qIn the given solution how did (a^{2}+ b^{2})^{2}- 2a^{2}b^{2}/ a^{2}b^{2 }changed into [(a + b)^{2}- 2ab ]^{2 }- 2(ab)^{2}/ (ab)^{2}i didnt understand how -2a^{2}b^{2}/ a^{2}b^{2 }change to^{}- 2(ab)^{2}/ (ab)^{2 }bcoz a^{2}b^{2}and (ab)^{2}are two different things. I guess !!i m confused..plzz help...how to calculate mode if two classes have same and highest frequency (bimodal) ?