math

what is the position of the image when an object is placed at a distance of 20 cm from a concave mirror of focal length 20cm?

math

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^{x }+ 2^{y}= 2^{x+y}, show that dy/dx = -2^{y-x}_{If y=cos inverse (sinx+cosx/ root 2) where - pi/4<x<pi/4, then find dy/dx.}9. A particle moves along a path ABCD as shown in the figure. Then the magnitude of net displacement of the particle from position A to D is :

$\left(1\right)10\mathrm{m}\left(2\right)5\sqrt{2}\mathrm{m}\left(3\right)9\mathrm{m}\left(4\right)7\sqrt{2}\mathrm{m}$

^{2}+(a.b)^{2}=144 and (a) =4, then (b) is equal towhat is the position of the image when an object is placed at a distance of 20 cm from a concave mirror of focal length 20cm?