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Kushal Aggarwal
Subject: Maths
, asked on 30/5/18
A point O is taken inside a rhombus ABCD such that distance from vertices B and D are equal. Show that AOC is straight line
Answer
0
J S
Subject: Maths
, asked on 30/8/17
PYTHAGORAS THEOREM.
Q.13. Find the area and the perimeter of a square whose diagonal is 10 cm long.
Answer
1
Puja Ahuja
Subject: Maths
, asked on 28/3/22
In triangle PQR , PQ=PR,QN=RM prove angle QPM =angle RPN
Answer
1
Ayush Chanderia
Subject: Maths
, asked on 2/10/18
In the given figure AE bisects ext angle CAD and AE is parallel to BC
Answer
1
Vinay Don
Subject: Maths
, asked on 10/12/17
Solve this:
Q. Prove that
∆
ABC
is right-angled at
A
if
AB
= 2
n
+ 1,
AC
= 2
n
(
n
+ 1) and
BC
= 2
n
(
n
+ 1) + 1.
Answer
1
Harpreet
Subject: Maths
, asked on 15/11/17
In the adjoining figure ABC is right angled triangle at B . ADEC and BCFG are squares. Prove that AF =BE.
Answer
0
Yashi❤️
Subject: Maths
, asked on 18/7/18
Plz solve Q.12
Answer
1
Chandrashekhar
Subject: Maths
, asked on 20/2/18
in figure 12.34 DE||BC if dc and be meet at o prove that triangle bod and triangle coe are equal in area
Answer
0
Khushboo
Subject: Maths
, asked on 8/9/17
Q. Using ruler and compasses only. Construct a rhombus ABCD with sides of length 4 cm, and diagonal AC of length 5 cm, measure
<
ABC.
Answer
2
Tejashree J Pillai
Subject: Maths
, asked on 31/10/17
in triangle ABC angle B =90 degree . find the sides of the triangle , if AB= (x-3) ,AC =(x+6) , BC=(x +4)
Answer
2
Zeba Chowdhury
Subject: Maths
, asked on 8/4/21
In the figure,PQRS is a square.Arc AB is drawn with centre P and any radius less than PR, cutting SR at A and RQ at B. Prove that AS=BQ
Answer
1
spptrail...
Subject: Maths
, asked on 9/8/18
Solve Q9 its urgent
Answer
4
Khushboo
Subject: Maths
, asked on 6/9/17
Q.38. In the adjoining figure, TR = TS,
∠
1
=
2
∠
2
a
n
d
∠
4
=
2
∠
3
. Prove that RB = SA.
Answer
1
Probin Sarkar
Subject: Maths
, asked on 5/7/19
Solve it urgent
In the given figure, ABCD is a square and ∆PAB is an equilateral triangle.
(i) Prove that ∆APD ≌ ∆BPC.
(ii) Show that ∠DPC = 15°.
[
Hint.
(i) ∠PAD = 90º + 60º = 150º and ∠PBC = 90º + 60º = 150º
(ii) ∠PAD = 150º and AP = AD ⇒ ∠APD = ∠ADP = 15º.
Answer
1
Abhijit Singha
Subject: Maths
, asked on 3/5/18
Q. BEC is an equilateral triangle in square ABCD, find the value of x.
Answer
3
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Q.13. Find the area and the perimeter of a square whose diagonal is 10 cm long.
Q. Prove that ABC is right-angled at A if AB = 2n + 1, AC = 2n (n+ 1) and BC = 2n (n + 1) + 1.
In the given figure, ABCD is a square and ∆PAB is an equilateral triangle.
(i) Prove that ∆APD ≌ ∆BPC.
(ii) Show that ∠DPC = 15°.
[Hint. (i) ∠PAD = 90º + 60º = 150º and ∠PBC = 90º + 60º = 150º
(ii) ∠PAD = 150º and AP = AD ⇒ ∠APD = ∠ADP = 15º.