find the equation of the circle passing through origin and cutting off intercepts a and b from x axis and y axis
one diameter of the circle circumscribing the rectangle ABCD is 4y=x+7.If the coordinates of A & B are (-3,4) &(5,4) respectively , find the equation of the circle.
Find the standard equation of ellipse whose focus is (1,0), the directrix is x+y+1=0 and eccentricity is 1/root2
A circle of constant radius 'a' passes through origin 'O' and cuts the coordinate axes in points P and Q, then the equation of the locus of the foot of perpendicular from O to PQ is(a) (x^2+y^2)(1/x^2+1/y^2)=4a^2(b) (x^2+y^2)(1/x^2+1/y^2)=a^2(c) (x^2+y^2)^2(1/x^2+1/y^2)=4a^2(d) (x^2+y^2)(1/x^2+1/y^2)=a^2
a tangent to the ellipse x2 + 4y2=4 meets the ellipse x2+2y2=6 at P and Q.the angle between the tangents at P and Q of the ellipse x2 +2y2=6
if the line 2x - y +1 = 0 touches the circle at the point (2,5) and the center of the circle lies on the line x+y -9 =0 find the eqn of circle
the tangent to curv y= x^2 + 6 at a point 1,7 touches the circle x^2+y^2+16x+12y+c=0 at a point q then the coordinates of q are :
ans = -6,-7
Find the equation of the circle passing through the points (4, 1) and (6, 5) and whose centre is on the line 4x + y = 16.
how can we derive standard equation of ellipse
find the equation of the circle passing through origin and cutting off intercepts a and b from x axis and y axis
one diameter of the circle circumscribing the rectangle ABCD is 4y=x+7.If the coordinates of A & B are (-3,4) &(5,4) respectively , find the equation of the circle.
Find the standard equation of ellipse whose focus is (1,0), the directrix is x+y+1=0 and eccentricity is 1/root2
A circle of constant radius 'a' passes through origin 'O' and cuts the coordinate axes in points P and Q, then the equation of the locus of the foot of perpendicular from O to PQ is
(a) (x^2+y^2)(1/x^2+1/y^2)=4a^2
(b) (x^2+y^2)(1/x^2+1/y^2)=a^2
(c) (x^2+y^2)^2(1/x^2+1/y^2)=4a^2
(d) (x^2+y^2)(1/x^2+1/y^2)=a^2
a tangent to the ellipse x2 + 4y2=4 meets the ellipse x2+2y2=6 at P and Q.the angle between the tangents at P and Q of the ellipse x2 +2y2=6
if the line 2x - y +1 = 0 touches the circle at the point (2,5) and the center of the circle lies on the line x+y -9 =0 find the eqn of circle
the tangent to curv y= x^2 + 6 at a point 1,7 touches the circle x^2+y^2+16x+12y+c=0 at a point q then the coordinates of q are :
ans = -6,-7
A tangent to the ellipse 4x2+9y2=36 is cut by the tangent at the extremities of the major axis at T and T'. The circle on TT' as diameter passes through the point
(A) (0-5) (B) ( 5, 0 )
(C) (0,0) (D) (3,2)
Find the equation of the circle passing through the points (4, 1) and (6, 5) and whose centre is on the line 4x + y = 16.
how can we derive standard equation of ellipse