Find the sum of digits of the resultant number in square of 2245?
The regular method will be to multiply 2245 with 2245 and then add the digits of the resultant number. Do we have any other simpler method? Any tip or rule? (Asked by Raina's parent)
9018723465 -:- 1230654789
28854 dived by 9
dear experts,in maths practice if we input the correct answer it says it is wrong
ex:92721
x 3
278163(my input)
potu's reply: wrong
92721
288163(potu's reply)
many more questions are like this,EXPERTS please recnify these mistakes please as if that one was correct i would have got a crown
what is (99)2
why do we do division started by left but not by right 9/108-12 but why dont right side 9/108-021
Multiplication by 1-digit numbers and by 10 example 5x4x6 ?
use compensation method of subtract 482 from 5661
which fo the following numbers are divisible by 3and 5
which of the following numbers are divisible by 9 and 2 ?
(I) 360 (II) 1214 (III) 7218 (IV) 9059
Find the sum of digits of the resultant number in square of 2245?
The regular method will be to multiply 2245 with 2245 and then add the digits of the resultant number. Do we have any other simpler method? Any tip or rule? (Asked by Raina's parent)
It is very urgent
9018723465 -:- 1230654789
28854 dived by 9
dear experts,in maths practice if we input the correct answer it says it is wrong
ex:92721
x 3
278163(my input)
potu's reply: wrong
92721
x 3
288163(potu's reply)
many more questions are like this,EXPERTS please recnify these mistakes please as if that one was correct i would have got a crown
what is (99)2
why do we do division started by left but not by right 9/108-12 but why dont right side 9/108-021
Multiplication by 1-digit numbers and by 10 example 5x4x6 ?
use compensation method of subtract 482 from 5661
which fo the following numbers are divisible by 3and 5
(I) 1360 (II) 2700 (III) 3999 (IV) 7980which of the following numbers are divisible by 9 and 2 ?
(I) 360 (II) 1214 (III) 7218 (IV) 9059