0.1 M KI and 0.2 AgNO3 are mixed in 3:1 volume ratio. Find the depression in freezing point of the resulting solution. (By assuming Kf H2O=2Kkg/mol)

Dear student,

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  • 11
The answer is (-0.25°C)
  • -15
@Kharanshu The answer mentioned was ​ΔT​f = 0.3 K kg/mol, i.e. that is the freezing point of the solution is -0.3K
  • -13
0.25k
  • -16
0.279
  • -11
0.279k
  • -8
1.86k
  • -10
Uuki
  • -16
0.1 molar potassium iodide and 0.2 molar AG and O3 are mixed in 3 is to 1 ratio volume ratio the depression of freezing point of the resulting solution will be if ke of H2O is equal to 1.8 66 KV in KG per mole
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0.379k
  • -12
0.279k
  • -11
0.1 molar potassium iodide 10.2 molality silver nitrate are mixed in 3621 volume ratio the depression of freezing point of the resulting solution will be if key of H2 equal to 1.86 kelvin kg per mole
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Enjoy buddy

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