0.6 ml of glacial acetic acid is with density 1.06 gram per litre is dissolved in 1 kg of solvent solution froze- 0.0 205 degree Celsius calculate van't Hoff factor

Given ,

Volume of acid = 0.6 ml, density = 1.06g/ml

Therefore, mass of acetic acid, w = 0.6 x 1.06 = 0.636 g

Molecular mass of acetic acid = 60 g

Mass of 1 L water = 1000 g

Now,

Dissociation of acetic acid:

CH3COOH  →  CH3COO^-  +  H⁺

   1-   

Now,

i =1 -  +  + = 1+

1.04 – 1 =

 = 0.04

Dissociation constant,