??(0.6a2?? 0.04b3)2?= (0.6a2)2?? 2 (0.6a2) (0.04b3) + (0.04b3)2.explain me this.

??(0.6a2?? 0.04b3)2?= (0.6a2)2?? 2 (0.6a2) (0.04b3) + (0.04b3)2.explain me this. + Expansions CONCEPTS . 3ax+ 5by TESTS 16:24 REVISION 3ax +2 3ax 5by + 5by = 9a2X2 + 30abxy + 25b2y2 (b) The given expression is (0.6a2 - 0.04b3)2, which is of the form (a - b)2. Thus, we can use the identity (a - b)2 = a2 - 2ab + b2 :. (0.6a2 - 0.04b3)2 = (O.6a2)2 - 2 (0.6a2) (0.04b3) + (0.04b3)2 = 0.36a4 - 0.048a2b3 + 0.001 6b6 (c) The given expression is -1+-,n form (a + b)2. , which is of the Thus, we can use the identity (a + b)2 = a2 + 2ab + b2 7 9 2 24 16 49 35 25 Example 3: TOPICS

Dear Student,
The formula

{(x - y)}^{2} = x^{2} - 2 xy + y^{2} is used here with x = 0.6 a^{2} and y = 0.04 b^{3} so {(0.6 a^{2} - 0.04 b^{3})}^{2} = {(0.6 a^{2})}^{2} - 2 \times 0.6 a^{2} \times 0.04 b^{3} + {(0.04 b^{3})}^{2} = 0.36 a^{4} - 0.048 a^{2} b^{3} + 0.0016 b^{6}