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08 What is masimum S. A is at height of 98 m above packet is dropped from much time and With What ground ? Take g 9 S ms it (Ans. 6.12 s. 45.98 6. A stone is dropped from a balloon rising upwards a velocity of 16 ms-l. stone reaches ground in 4 s. Calculate the height Of the balloon (Ans. 14.4 m) 7. From the top of a tower I(X) m in height a ball is dropped and at the same time anoüier ban is projected vertically upwards from the ground with velocity of 25 msL 1. Find when and where two balls will meet. Take g = 9.8 ms- 2. (Ans. 78.4 from top, 4 s) 8. A body is dropped from rest at a height of m. and simultaneously, another body is dropped frorn —rest from a point 100 m above the ground. What is their difference in height after they have fallen (1) 2 s 3 s ? How does the difference in hei#tt vary with time ? Take g = 10 ms- (Ans. m, difference in hei*tt remains constant at 50 m) 9. A body falling freely under gravity passes two ints 30 m apart in Is. Find from what point above or

Dear Student ,
 

let

h1 = 150 m  and  h2 = 100 m 

and we know

s = ut + (1/2)at2

or as in this case, u =0 and a = -g

so

s = -(1/2)gt2

or

s1 = s2 = -(1/2)gt2 = -(1/2)x10x(2)2 = 20 m

which is the distance travelled by the two objects.

 

now the height of the stone 1 after 2 seconds will be

h'1 = 150 - 20 m = 130 m 

 

and similarly for stone 2

h'2 = 100 - 20 = 80 m

 

so, the difference in heights will still be = 130 - 80 m = 50 m

and their difference in height would stay constant until stone 2 touches the ground.

Regards

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acceleration due to gravity does not depend on mass or weight of body, provided air resistance is negligible. This was experimentally proven by galileo. The only thing to be taken care of is that the bodies may not reach ground before the given time interval. Here in 3 seconds, bodies do not reach ground. So distance between them will remain constant.
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