1.1 mole of A is mixed with 1.2 mole of B and the mixture is kept in a 1L flask till equilibrium A+2B2C+D is reached. At equilibrium 0.1 mole of D is formed. The Kc of reaction is

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    A     +   2B       2C  +  D    1.1          1.2              0          0                    (Initial)1.1-x     1.2-2x       2x         x                (At equilibrium)But x = 0.1Therefore, at equilibrium, [A] = 1.1-0.1=1[B]=1.2-2(0.1)=1[C]=2(0.1)=0.2[D]=0.1Therefore, K=[C]2]D][A][B]2or, K=(0.2)2(0.1)(1)(1)2= 4×10-3

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