1 17g of menthol cxhyoz burns in air to give 3 3 g of co2 and 1 35g of h20 - Chemistry - Some Basic Concepts of Chemistry

Question

1 17g of menthol cxhyoz burns in
air to give 3 3 g of co2 and 1 35g of h20 what is the empirical
formula of menthol if the combustion reaction can be represented
as
a C1OH10O B C2HO2 C C10H20O D C10H5O2

Akanksha C. · Accepted Answer

Dear Student,Menthol + Oxygen --> CO2    + H2O1
17 g                                       3
3 g        1
35gMass of carbon = 3
3 ×1244 =0
9 gMass of Hydrogen =1
35×218 = 0
15 gMass of oxygen =1 17-0 9+0 15 =0
12 gMoles of carbon =massMolar mass =0
9 12=0 075 Moles of Hydrogen = 0
152 =0 075Moles of oxygen =0 1216 =0
0075Molar ratio of carbon = 0 0750
0075 =10Molar ratio of Hydrogen= 0 0750
0075 =10Molar ratio of oxygen = 0
00750
0075 =1So, emperical formula is C10H10O

1.17g of menthol cxhyoz burns in air to give 3.3 g of co2 and 1.35g of h20. what is the empirical formula of menthol if the combustion reaction can be represented as a. C1OH10O B. C2HO2 C. C10H20O D.C10H5O2

1.17g of menthol c_xh_yo_z burns in air to give 3.3 g of co2 and 1.35g of h20. what is the empirical formula of menthol if the combustion reaction can be represented as
a. C_1OH₁₀O B. C2HO2 C. C10H20O D.C10H5O2