1) 2 circles touch internally at point P. From a point T on the common tangent at P, tangent segments TQ and TR are drawn to the circles. Prove that TQ =TR.
Hi!
Here is the answer to your question.
Given: Circles with centers C1 and C2 touch each other internally at P. TP is the common tangent to the circles. TQ and TR is a tangent to circle with centres C1 and C2, respectively
To prove: TQ = TR
Proof:
TP and TQ are tangents drawn from an external point T to the circle with centre C1
So, TQ = TP … (1) (length of tangents drawn from external point to circle are equal)
Similarly, considering the smaller circle,
TR = TP … (2)
From (1) and (2), we get
TQ = TR
Cheers!