1) 2 circles touch internally at point P. From a point T on the common tangent at P, tangent  segments TQ  and TR are drawn  to the circles. Prove that TQ =TR.

Hi! 
Here is the answer to your question.
 
Given: Circles with centers C1 and C2 touch each other internally at P. TP is the common tangent to the circles. TQ and TR is a tangent to circle with centres C1 and C2, respectively
To prove: TQ = TR
Proof:
TP and TQ are tangents drawn from an external point T to the circle with centre C1
So, TQ = TP   … (1)  (length of tangents drawn from external point to circle are equal)
Similarly, considering the smaller circle,
TR = TP     … (2)
From (1) and (2), we get
TQ = TR
 
Cheers!

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when 2 circles touch at P, the tangent with P as the point of contact has a point T lyingf on it. TQ and TR are drawn from T to the circle.   pl tell us the position of  Q and R.

if Q and R are the centres of the circle, them TQ is not = TR.

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