# 1 2 correct alternative

eqn of line = x - 1 / a = y + 2 /b = z - 5 /c ..............1

perpendicular to i + j +k

a + b + c = 0 .......... 2

perpendicular to i - 2j + 3k

a - 2b + 3c = 0 .........3

on solving 2 and 3

a/5 = b/-2 = c/-3 = lambda

a = 5 lambda

b = -2 lambda

c = -3 lambda

substitute in eqn 1 and cancel lambda

x - 1 / 5 = y + 2 / -2 = z - 5 / -3

hope it helps