1 2 correct alternative

a vector = i - 2j  + 5k
eqn of line = x - 1 / a = y + 2 /b = z - 5 /c    ..............1
perpendicular to i + j +k 
a + b + c = 0 .......... 2
perpendicular to i - 2j + 3k
a - 2b + 3c = 0 .........3

on solving 2 and 3 
a/5 = b/-2 = c/-3 = lambda
a = 5 lambda 
b = -2 lambda
c = -3 lambda
substitute in eqn 1 and cancel lambda
x - 1 / 5 = y + 2 / -2 = z - 5 / -3
hope it helps