1.5 g of cdcl2 was found to contain 0.9 g of cd. Calculate the atomic weight of Cd

(0.9 g Cd) / (1.5 g CdCl2) = 0.60 = 60% Cd 100% total - 60% Cd = 40% Cl (70.9064 g Cl2/mol) / 0.40 = 177.266 g/mol total (177.266 g/mol total) - (70.9064 g Cl2/mol) = 106 g/mol Cd Hope dis hlps
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