1.5 g of cdcl2 was found to contain 0.9 g of cd. Calculate the atomic weight of Cd
(0.9 g Cd) / (1.5 g CdCl2) = 0.60 = 60% Cd
100% total - 60% Cd = 40% Cl
(70.9064 g Cl2/mol) / 0.40 = 177.266 g/mol total
(177.266 g/mol total) - (70.9064 g Cl2/mol) = 106 g/mol Cd
Hope dis hlps