{1 a2+bc a3

1 b2+ca b3

1 c2+ab c3} = -(a-b) (b-c) (c-a) (a2 +b2+c2) using properties of determinannts solve

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Question

{1 a2+bc a3
1 b2+ca b3
1 c2+ab c3} = -(a-b) (b-c) (c-a) (a2 +b2+c2) using properties of
determinannts solve

Tushar Kohli · Accepted Answer

{1 a2+bc a3 1 b2+ca b3 1 c2+ab c3} = -(a-b) (b-c) (c-a) (a2 +b2+c2) using properties of determinannts solve