1. Arrange the following as per the instruction given 
in the brackets • 
(i) Be, F, Li, O, C (decreasing order of atomic size). 
(ii) cs, Na, Li, K, Rb (increasing order of metallic character)
(iii) Na, K, Cl, S, Si (increasing order of ionization energy). 
(iv) Cl, F, Br, I ( increasing order of electron affinity). 

2. Compare the compounds Carbon tetrachloride and sodium chloride with regard to solubility in water and
electrical conductivity.

Dear student,
Atomic size increases down the group and decreases along the period from left to right.
Therefore, the correct order is Li>Be>C>O>F
Metallic character increases down the group and decreases along the period from left to right.
Therefore, the correct order is, Li<Na<K<Rb<Cs
The ionization enthalpy decreases down the group and increases along the period.
Therefore, the correct order is, K<Na<Si<S<Cl
The electron affinity decreases down the group and increases along the period from left to right. Due to  small  size of fluorine, it cannot easily accept electron compared to chlorine.
Therefore, the correct order is, I<Br<F<Cl
Hope this information will clear your doubts about topic.

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Regards

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[Ne] 3s² 3p⁴
 
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2. Cs,Rb,K,Na,Li
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