1.draw the graph for x-y+1=0,3x+2y-12=0. calculate the area bounded by these lives &x-axis.
2. solve the following pair of linear equation:-
1) 2x-3y=7 & x+y=1
2) x+1/2+ y-1/3=8 & x-1/3+y+1/2=9
3) 3(2u+v)=7uv & 3(u+3v)-11uv
4) 1/2x+1/3y=2 &1/3x+1/2y=13/6
The solution of the equation x - y + 1 = 0 is
| x | -1 | 2 |
| y | 0 | 3 |
The solution of the equation 3x+2y-12=0 is
| x | -2 | 4 |
| y | 9 | 0 |
now, plotting these points on graph as follows:
In the graph,
draw a perpendicular from point B(2,3) on x-axis and mark it as E
BE =height of triangle BAD = dist. b/w E and B = 3-0=3
and
AD = base of triangle = distance b/w A & B =4-(-1)=4+1=5
area of tr. BAD=(1/2) * base * height = =(1/2)*5*3=15/2=7.5 sq. units