1. Find the area of the shaded region in the figure if AC=24 cm ,BC=10 cm and o is the center of the circle (use

o

A [Ans- 145.33 cm²]

Try to find by solving areas of the sectors

by pyth. theorem
length of side ab=26cm
so the radius of semi circle is 13cm
 area of semicircle = 1/2 * 3.14 * 13 * 13 = 265.33cm²
 area of triangle=120 cm² 
area of semicircle + area of triangle = 385.33 cm²
area of circle = 530.66 cm²
area of shaded region= 530.66-385.33=145.33cm²
I hope that this answer will be useful to all 
ALL THE BEST 4 ur SAII
EXAMINATION..............
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                     Here, AC = 24 cm and BC = 10 cm and AOB is a diameter.
                     Since, angle in semicirle is a right angle, i.e., Angle ACB = 90⁰ 
                                 AB = Root AC² + BC²
                                        = Root 24² + 10²
                                        = Root 576 + 100
                                        = Root 676     = 26 cm.
                    Therefore, Radius of circle = 13 cm.
              
                     Now, area of the shaded region
                                         = Area of semicircle - Area of triangle ABC
                                         = 1  pie*r²  -  1  * BC * AC   
                                            2                  2
                                         =  1   * 3.14 * 13 * 13 -  1  * 24 * 10 
                                             2                                  2
                                         = 530.66  - 120   
                                                 2
                                         = 265.33 - 120
                                         = 145.33 cm² .
      Hope this helps.
                           
                                         

This is the answer guys!

O i will solve ur problem after exam

Observe the below pic for the answer

145.33 is the correct answer bro plz like a smile

keep full answer
 

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