1 g of carbonate (M2CO3) on treatment with excess HCl produces 0.01186 mole of CO2.Molar Mass of M2CO3 in g/mol is:-
(a)1186
(b)84.3
(c)118.6
(d)11.86
Need proper explanation and a step by step solution for the same?

Hi how s u
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  • 1
ok, so the reaction goes like this ... M2CO3   + 2 HCl  ---------- 2 MCl + H2O + CO2
we get to know that ... 1 mole of M2Co3 gives 1 mole of CO2
therefore, 0.01186mole of CO2 is produced when 0.01186 mole of M2CO3 is taken.  (1)
given : 1g of m2co3
so, 1g of m2co3 has 0.01186 moles (from 1)
molar mass = 1/0.01186=84.3g mol-1
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