1 g of pure calcium carbonate was found to require 50ml of dilute HCl for complete reaction.the strength of the HCl solution is given by Share with your friends Share 15 Geetha answered this CaCO3 + 2HCl → CaCl2 + H2O + CO21 g of CaCO3 requires 50 ml of dil HCl. The normality of 50 ml HCl required for this reaction is = Weight of CaCO3 given / Eq massvolume of the solution in L = 1/500.05 [ vol of HCl = 50 ml = 0.05 L) = 0.4 N 32 View Full Answer
