1 gm of charcoal adsorbs 100 ml 0.5 M CH3COOH to form a monolayer thereby the molarity of CH3COOH reduces to 0.49. Calculate the surface area of the charcoal adsorbed by each molecule of acetic acid. Surface area of charcoal= 3.01x 102 m2/gm.

Number of moles of acetic acid in given sample = concentration x volume
                                                                            = 0.5 mol L-1 x 0.1 L
                                                                           = 0.05 moles
Number of moles of acetic acid left after adsorption = 0.49 mol L-1 x 0.1 L
                                                                           = 0.049 moles
Number of moles of acetic acid adsorb on surface = 0.05 - 0.049 = 0.001 mol
Number of molecules adsorbs on surface = 0.001 x 6.022 x 1023 
                                                                  = 6.022 x 1020
Surface Area occupied by each molecule = total surface area of charcoal / Number of molecules of acetic acid
                                                                 = 3.01 x 102 m2 g-1/ 6.022 x 1020
                                                                 = 5. 0 x 10-19 m2 g-1
 

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