1)  if a , b , c are in AP  , show that 1/ab , 1/ca , 1/bc are in AP .

2) if m times the mth term of an AP is equal to n times it's n term ,  find the (m+n)th term.

pls answer fast...

2.Let a and d be the first term and common difference of A.P.
nth term of the A.P., an = a + (n – 1)d
Given, mam = nan
(m + n)th term of A.P = am + n
  = a + (m + n – 1)d
  = – (m + n – 1)d + (m + n – 1)d  (using (1))
   = 0
∴ (m + n)th term of A.P. is 0.
 
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1.Given,

a,b,c are in A.P.Let a=a1-d,b=a1,c=a1+d

=>2b=a+c=>(dividing by abc)=>2/ac=1/bc+1/ab,which can be written in d form:-2y=x+z,where x=1/bc=1st term -c.d ,y=1/ac=1st term & z=1/ab=1st term +c.d

hence,1/ab , 1/ca , 1/bc are in AP .

2.Refer 2 d steps given by neenu_qatar

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