1) In triangle ADE, BC is parallel to DE. Ar of triangle ABC = 25 sq.cm, ar of trapezium BCED = 24 sq.cm and DE = 14 cm. Calculate the length of BC. (this I found to be 10 cm). Also find the area of triangle BCD. ( I am stuck here).

2) In a trapezium ABCD, AB is parallel to DC and diagonals AC and BD intersect at point P. If AP : CP = 3 : 5, find : a) triangle APB : triangle CPB (b) triangle DPC : triangle APB (c) triangle ADP : triangle APB (d) triangle APB : triangle ADB.

area of ΔADE = ar (ΔABC) + ar (trapezium BCED)

= 25 + 24 = 49 cm^{2}.

In ΔABC and ΔADE,

let CF be the perpendicular distance between BC and DE.

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