Let I = ∫dxsin2x cos2x=∫42 sin x cos x2=4∫dxsin 2x2=4∫dxsin22x=4∫cosec22x dx=-4 cot 2x2 + C=-2 cot 2x + C

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⌠1/sin²xcos²x

Let I = \int \frac{d x}{\sin^{2} x . \cos^{2} x} = \int \frac{4}{{(2 \sin x \cos x)}^{2}} = 4 \int \frac{d x}{{(\sin 2 x)}^{2}} = 4 \int \frac{d x}{\sin^{2} 2 x} = 4 \int \cos e c^{2} 2 x d x = - 4 (\frac{c o t 2 x}{2}) + C = - 2 c o t 2 x + C

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⌠1/sin2xcos2x