1) tan 5 A - tan 3 A sin 2 A 2) cot A . cot 4 A + 1 cos 3 A
........................... = ............ ............................ = ............
tan 5 A + tan 3 A sin 8A cot A . cot 4 A - 1 cos 5 A
3) cot 6 A - tan 2 A cos 8 A
......................... = ............
cot 6 A + tan 2 A cos 4 A

Dear Student,

(1)

L.H.S.=tan 5A-tan 3Atan5A+tan3A            =sin 5Acos 5A-sin 3Acos 3Asin5Acos5A+sin3Acos3A            =sin 5A cos 3A-sin 3A cos 5Asin 5A cos 3A+sin 3A cos 5A            =sin5A-3Asin5A+3A            =sin 2Asin 8A            =R.H.S.Hence Proved.Kindly ask the remaining query in different thread.

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