1)the energy of an alpha particle is 1.2×10^-13J.up to what closet distance can it reach the nucleus of silver(Z=47)? Ans is 1.8×10^-13. Share with your friends Share 7 Govind answered this Energy of the alpha particle, E=1.2×10-13 JAtomic number of silver, Z=47Distance of closest approach is given byr=Ze2e4π∈0×12mv2⇒r=9×109×47×21.6×10-1921.2×10-13⇒r=1804.8×10-16 m⇒r=1.8×10-13 m 11 View Full Answer