1) The given figure shows a kite in which BCD is the shape of a quadrant of a circle of radius 42 cm. ABCD is a square and C E F is an isosceles right angled triangle whose equal sides are 6 cm long. Find the area of the shaded region.

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  • 1
area of shaded region = area of quadrant + area of triangle
                  (tita/360 * pi * r * r) + 1/2 bh
              (90/360 * 22/7 * 42 * 42) + (1/2 * 6 * 6) 
           (1/4 * 22 * 6 * 42) + (3 * 6)  = (11 * 6 * 21) + 18 =
              66 * 21 + 18 = 1386 + 16 = 1404
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