1 what is the geometry of Ni(CO)4 and [Ni(pph3)2]Cl are respectively 2 [Ni(CO)4] possesses tetrahedral geometry while [Ni(CN)4]2- is - Chemistry - Coordination Compounds

Question

1 what is the geometry of Ni(CO)4 and [Ni(pph3)2]Cl are
respectively?
2 [Ni(CO)4] possesses tetrahedral geometry while [Ni(CN)4]2- is
a sqare planar explain?

Urvashi Yadav · Accepted Answer

Geometry of [Ni(CO)4] is tetrahedral while geometry of [Ni(pph3)2Cl2] is square planner Geometry of [Ni(CO)4]:

Geometry of [Ni(pph3)2Cl2]:

[Ni(CO)4] is an unusual complex It has Ni in 0 oxidation state ,thus there are 8 electrons in 3d and 2 electrons in 4s CO is the strongest ligand and does cause pairing leaving 1 empty d orbital Now, somehow the paired electrons in 4s shift to 3d leaving 4s orbital empty and free to accommodate electrons from CO So, there are no free d orbitals as it is a weak ligand so it has sp3 hybridisation meaning tetrahedral shape

While in [Ni(CN)4]2- , In this Ni in +2 oxidation state, thus there are 8 electrons in 3d orbital and CN is a strong ligand so causes pairing of the Ni d-electrons, leaving empty d orbital so hybridisation is dsp2, square planar

1.what is the geometry of Ni(CO)4 and [Ni(pph3)2]Cl are respectively? 2.[Ni(CO)4] possesses tetrahedral geometry while [Ni(CN)4]2- is a sqare planar.explain?

1.what is the geometry of Ni(CO)4 and [Ni(pph3)2]Cl are respectively?

2.[Ni(CO)4] possesses tetrahedral geometry while [Ni(CN)4]2- is a sqare planar.explain?