1) Write the pythagorean triplet whose one member is 16.

2) Find the cube root of 8000

3) Find the smallest square number that is divisible by each of the numbers 8,15,20

4) Find the smallest whole number of 252 by which it should be multiplied so as get a perfect square number.Also find the square root of the new number.

5) Find the square root of

1 . 51.84

2 5776

Taking ${n}^{2}+1=16,\mathrm{then}{n}^{2}=15$

Here the value of

*n*will not be an integer.

Taking ${n}^{2}-1=16,\mathrm{then}{n}^{2}=17$

Here also the value of

*n*will not be an integer.

Taking $2n=16\Rightarrow n=8$

Thus, ${n}^{2}+1={8}^{2}+1=65\mathrm{and}{n}^{2}-1={8}^{2}-1=63$

Therefore the pythagorean triplet is 16, 63 and 65.

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