10^9 electrons pass from A to B in 10^-3 second.Calculate the strength of current and give its direction.
ans is 1.6*10^-7A.

Question

10^9 electrons pass from A to B in 10^-3 second Calculate the
strength of current and give its direction
ans is 1 6*10^-7A

Akansha Tyagi · Accepted Answer

Current,i=net  i=1 6×10-19×10910-3=1
6×10-7ACurrent will be in opposite direction of flow of electron i
e  from B to A