10. Find the maximum energy that beta-particle may have in the following decay: 

a.  O 19 8   F 19 9 + e 0 - 1 + v
Given 
 
m ( O 19 8   ) = 19.003576 a.m.u. 
m ( F 19 9 ) = 18.998403 a.m.u. 
m ( e 0 ) = 0.000549 a.m.u. 

Dear Student,


mass difference =19.003576-18.998403-0.000549=0.004624maximum energy =0.004624931.5 MeV=4.31 Mev is the maxium energy of the beta particle.regards

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