10. Find the maximum energy that beta-particle may have in the following decay: a. O 19 8 → F 19 9 + e 0 - 1 + v Given m ( O 19 8 ) = 19.003576 a.m.u. m ( F 19 9 ) = 18.998403 a.m.u. m ( e 0 ) = 0.000549 a.m.u. Share with your friends Share 11 Shobhit Mittal answered this Dear Student, mass difference =19.003576-18.998403-0.000549=0.004624maximum energy =0.004624931.5 MeV=4.31 Mev is the maxium energy of the beta particle.regards 10 View Full Answer