10 ml each of 0.1 M Bacl2 and K2SO4 are mixed. which will have the highest concentration in the solution?

Here volume of solution = 10 ml + 10 ml = 20 ml
Now, no. of moles of BaCl₂  = Molarity x volume = 0.1 x 0.01 L = 0.001 moles 
Further, no. of moles of K₂SO₄ = Molarity x volume = 0.1 x 0.01 L = 0.001 moles 
Now, 1 mole of BaCl₂ = molar mass = 208 gm
So, 0.001 mole of BaCl₂ = 208 x 0.001 = 0.208 gm
Similarly , 0.001 mole of K₂SO₄ = 174 x 0.001 = 0.174 gm
So, Concentration of BaCl₂ = 0.208/ 0.02 = 10.4 gm/L
Similarly concentration of K₂SO₄ = 0.174/ 0.02 =8.7 gm/L
Hence, BaCl₂ has teh highest concentration.