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​. 100 ml CuS04(aq) was electrolyzed using inert electrodes by passing 0.965 A till the pH of the resulting solution was l. The solution after electrolysis was neutralized, treated with excess KI and titrated with 0.04 M Na2S203. Volume of Na2S203 required was 35 ml. Assuming no volume change during electrolysis, Calculate : (a) duration of electrolysis if current efficiency is 80% (b) initial concentration (M) of CuS04.

Dear Student,

The computation is as expressed below,

(a) pH = 1 [conc] = 0.1 M vol = 100 ml = 0.1 ltno.of moles = 0.1 mollt0.1 lt=1 mol 1 F of chargeCu2++2e-Cuso duration of electrolysis is,Q=Itt =QI=96487×1 F0.965=99986.5285 sec99986.5285 3600=27.77 hrsfor 80% efficiency is 80% 27.770.8=34.71 hrs(b) initial concentration of CuSO4pH=1[H+]=10-1=0.1 M

Regards.

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