100 ml of 0.1 m nacl solution is mixed with 100 ml of 0.2 m of agno3 solution.find the mass of agcl precipitate formed.which reactant is acting as limiting raegent

The reaction taking place is as follows:
       AgNO3 + NaCl → NaNO3 + AgCl
Number of moles of AgNO3 = M x V
                                               = 0.2 mol / L x 0.1 L
                                               = 0.02 mol
Number of moles of NaCl     = M x V
                                               = 0.1 mol / L x 0.1 L
                                               = 0.01 mol
Thus,
      More AgNO3 is present than required.
Hence,
      NaCl is the limiting reagent.
Number of moles of AgCl obtained = 0.01 mol
Hence,
      Mass of AgCl formed = 0.01 x 143.5
                                          = 1.435 g AgCl

 

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