100 ml of 0.1 N NaOH is mixed with 100 ml of 0.1 N H2SO4.The pH of the resultant solution is??

NaOH  volume = 100ml or 0.1L 
Normality =0.1 N
molarity=normality= 0.1M
moles of NaOH =  0.1×0.1 = 0.01mol  [using formula  mole = C (concentration in M) ×V in L]

H2SO4 volume = 100ml or 0.1L 
Normality= 0.1 N
number of electron change (n) for H2SO4  = 2
Thus molarity = 0.05 M  ( since N = M ×n)
Moles of H2SO4 = 0.1×0.1 = 0.005 mol

0.01 mole of NaOH exactly neutralizes 0.005 mole of H2SO4 according to the reaction
NaOH + H2SO4 Na2SO4 + H2O
Thus neither NaOH is in excess nor H2SO4 therefore solution will be neutral and hence
pH= 7

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