100 mL of 10% NaOH (w/V) is added to 100 mL of 10% HCl (w/V). The resultant solution becomes :- (1) alkaline (2) strongly alkaline (3) acidic (4) neutral
the answer given is acidic. How ?

Dear student

10% NaOH=10g NaOH in 100mLmol of NaOH present =10/40 =0.25 molMoles OfHCl present =10/36.5 =0.274 molMoles of HCl> Moles of NaOHThus the resultimg solution is acidic.
Regards

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This is because substances react in terms of their moles and here even though there mass by volume percentage are same , there moles are different. Thus one of them is limiting and the oyher is in excess and it is the one in excess which will determine the pH of resultant sol.On calculating we find HCl is in excess as follows

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