106-2 triangle ABC is similar to triangle pqr, PM is median of TRIANGLE PQR.lIf ar triangle abc = 289 cm2, BC=17 DEGREE mr=6.5cm,then the area of triangle pqm is




We have,ABC~PQR   givenarABC = 289 cm2BC = 17 cmNow, MR = 6.5 cmSince PM is median to side PR of PQR, so     QR = 2 MRQR = 2×6.5 = 13 cmWe know that ratio of areas of 2 similar 's is equal to squares of the ratio of their corresponding sides.   arABCarPQR = BCQR2289arPQR = 17132arPQR = 169 cm2We know that median of a  divides it into 2 's of equal areas.So, arPQM = 12arPQR = 12×169 = 84.5 cm2

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