107 to the power 1444 is a no which when divided by 136 find last 2 digit and remainder Share with your friends Share 0 Lovina Kansal answered this Dear student First find out last two digit numbers;1071444=100+71444=1444C0100071444+1444C1100171443.....We should ignore the rest because, in 2nd term 100 came , which means we have to only evaluate 1 stem to find last 2 digit;So,1444C0100071444=71444Now check cyclicity of 771=772=4973=34374=240175=1680776=117649So, cyclicity of 7 is 4;Let us divide 1444 with 4, we geti.e., 14444=361Here remainder is zero, last two digit of 71444 is 07Hence last 2 digit of 1071444 is 07Now let us find out remainder if 1071444 is divided by 136.1071444136=1072722136=11449722136If we divide 11449 by 136 remainder is 25, so;25722136=252361136=625361136If we divide 625 by 136 remainder is 81,s81361136=81×81360136=81×812180136=81×6561180136If we divide 6561 by 136 remainder is 33,So81×33180136=81×33290136=81×108990136If we divide 1089 by 136 remainder is 1.So,81×19=81So, remainder is 81 Regards -4 View Full Answer
