10g of a piece of marble was put into excess of dilute HCl acid Wgen the reaction was complete - Chemistry - States of Matter

Question

10g of a piece of marble was put into excess of dilute HCl acid
Wgen the reaction was complete , 1120cc of CO2 was obtained at STP
The percentage of CaCO3 in marble is

Geetha · Accepted Answer

CaCO3 + 2 HCl → CaCl2 + H2O + CO2100 g                                                       22400 cc 100 g of CaCO3 gives 22400 cc of carbon dioxide
10 g of CaCO3 gives = 22400100  × 10 = 2240 cc of carbon dioxide
If the metal is 100 % pure, 2240 cc of carbondioxide is produced
 1120 cc of carbon dioxide is produced in this case
 So the % purity = 1002240  × 1120  = 50 %

10g of a piece of marble was put into excess of dilute HCl acid. Wgen the reaction was complete , 1120cc of CO2 was obtained at STP. The percentage of CaCO3 in marble is