10th 10 Find the range of values of 'a' if the roots of the equation x2+a2=8x+6a are - Maths - Quadratic Equations

Question

10th

10 Find the range of values of 'a' if the roots of the equation
x2+a2=8x+6a are real

Neha Sethi · Accepted Answer

Dear student
x2+a2=8x+6ax2-8x+a2-6a=0since the roots of this equation are real,the discriminant of this equation must be ≥0D=B2-4AC-82-41a2-6a≥064-4a2+24a≥04a2-24a-64≤0a2-6a-16≤0a2+2a-8a-16≤0a(a+2)-8(a+2)≤0(a-8)(a+2)≤0Hence for (a-8)(a+2)≤0, a should belong to the interval -2,8
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10th 10. Find the range of values of 'a' if the roots of the equation x2+a2=8x+6a are real.

10th

10. Find the range of values of 'a' if the roots of the equation x²+a²=8x+6a are real.