11 question Share with your friends Share 0 Rahul Raj answered this dear student du=cos(mcos-1x)m-11-x2dv=-sin(msin-1x)m11-x2LHS=dudv=cos(mcos-1x)m-11-x2-sin(msin-1x)m11-x2=cos(mcos-1x)sin(msin-1x)RHS=1-u21-v2=1-sin2(mcos-1x)21-cos2(msin-1x)2=cos(mcos-1x)sin(msin-1x) regards 0 View Full Answer Jegannathan Anandaraman answered this Hello friend, here is the answer 0