112 ml of a gas is produced at STP by the action of 412 mg of alcohol ROH with CH₃Mgl. The molecular mass of alcohol is,
CH₃Mgl + ROH -- > CH₄(g) + R-OMg-l
A)32g
B)41.2g
C)82.4g
D)156g

Question

112 ml of a gas is produced at STP by the action of 412 mg of
alcohol ROH with CH3Mgl The molecular mass of alcohol
is,
CH3Mgl + ROH -- > CH4(g) + R-OMg-l
A)32g
B)41 2g
C)82 4g
D)156g

Tinku Jangra · Accepted Answer

ROH + CH3MgI→CH4  + RO-MgI+Volume of gas produced = 112 mLMass of alcohol used = 412 mg1 mole of alcohol produce 1 mole of CH4
So, 22
4 L CH4 will be produced by the molecular weight of alcohol
112 mL CH4 is produced from 412 mg of alcoholSo, 22400 mL of CH4 will be produced by = 412112×22400=82400 mg of alcohol = 82
4 g of ROHSo, molecular mass of alcohol will be = 82
4 g
Option C is correct

112 ml of a gas is produced at STP by the action of 412 mg of alcohol ROH with CH3Mgl. The molecular mass of alcohol is, CH3Mgl + ROH -- > CH4(g) + R-OMg-l A)32g B)41.2g C)82.4g D)156g

112 ml of a gas is produced at STP by the action of 412 mg of alcohol ROH with CH₃Mgl. The molecular mass of alcohol is,
CH₃Mgl + ROH -- > CH₄(g) + R-OMg-l
A)32g
B)41.2g
C)82.4g
D)156g