11th ans pls 11. A stone is falling freely in free space. Its velocity is
x when it has lost y units of potential energy in the
gravitational field of earth. The mass of the stone is
2y
(2)
2
x
— + 9.8
(4)
x
. Aakash T
Given freely falling, so initial velocity U=0;
also potential energy is Y=mgh => m = Y / gh - (1);
by eqn v2 =2gh => h = v2 / 2g; since v=x, h=x 2/ 2g -(2) ;
substitute h in eqn 1
we get m = 2y / x2