12 5 ml 4NHNO3, 40ml 5M HCl and x ml of 3M H2SO4 are mixed together and volume is made - Chemistry - Basic Concepts in Chemistry

Question

12 5 ml 4NHNO3, 40ml 5M HCl and x ml of 3M H2SO4 are mixed together
and volume is made 1 litre by adding water 50 ml of this solution
is completely neutralized by 25 ml of 0 5M Na2CO3 solution, what is
the value of x - (1) 62 5 ml (2) 41 67 ml (3) 72 7 ml (4) 57 25 ml

Vartika Jain · Accepted Answer

Dear Student,

miliequivalent of HNO3=N1V1=4N×12
5 ml=50 miliequivalent of HCl =N2V2= 5N×40 ml=200       ( for HCl, M=N)miliequivalent of H2SO4=N3V3 = 2×3N ×x ml        (for H2SO4, N=2M)Normality of the resulting mixture can be calculated asN1V1+N2V2+N3V3=N4V4or, 50+200+6x=N4×1000or, N4 = 50+200+6x1000Now, For complete neutralisation, N4V4(mixture)=N5V5(Na2CO3)Now, miliequivalent =N5V5= 5N×40 m =2×0
5 N×25 ml=25   (for Na2O3, N=2M)or, 50+200+6x1000×50=25or, 50+200+6x=500or, 6x=500-200-50=250or, x=2506=41
67 mlHence, correct answer is (2)

12.5 ml 4NHNO3, 40ml 5M HCl and x ml of 3M H2SO4 are mixed together and volume is made 1 litre by adding water. 50 ml of this solution is completely neutralized by 25 ml of 0.5M Na2CO3 solution, what is the value of x - (1) 62.5 ml (2) 41.67 ml (3) 72.7 ml (4) 57.25 ml