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12⁴* 9³* 4 / 6³* 8²* 27 = 81 if it is wrong solve and tell me the correct answer

$\frac{12^{4} \times 9^{3} \times 4}{6^{3} \times 8^{3} \times 27} = \frac{{(2 \times 2 \times 3)}^{3} \times (3 \times 3)^{3} \times (2 \times 2)}{{(2 \times 3)}^{3} \times (2 \times 2 \times 2)^{3} \times (3 \times 3 \times 3)} = \frac{{(2^{2} \times 3)}^{4} \times (3^{2})^{3} \times (2)^{2}}{2^{3} \times 3^{3} \times (2^{3})^{3} \times 3^{3}} = \frac{(2^{2})^{4} \times 3^{4} \times 3^{2 \times 3} \times 2^{2}}{2^{3} \times 3^{3 + 3} \times 2^{3 \times 3}} = \frac{2^{2 \times 4} \times 3^{4} \times 3^{6} \times 2^{2}}{2^{3} \times 3^{6} \times 2^{9}} = \frac{2^{8 + 2} \times 3^{4 + 6}}{2^{3 + 2} \times 3^{6}} = \frac{2^{10} \times 3^{10}}{2^{12} \times 3^{6}} = \frac{3^{10 - 6}}{2^{12 - 10}} = \frac{3^{4}}{2^{2}} = \frac{3 \times 3 \times 3 \times 3}{2 \times 2} = \frac{81}{4} = 20.25$

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