14) A gaseous mixture containing 50 g of nitrogen and 10 g of oxygen were enclosed in a vessel of - Chemistry - States of Matter

Question

14) A gaseous mixture containing 50 g of nitrogen and 10 g of
oxygen were enclosed in a vessel of 10 L capacity at 27 °
  C Calculate :
a) the number of moles of each gas
b) the partial pressure of each gas
c) the total pressure of the gaseous mixture

Geetha · Accepted Answer

a) Number of moles = Given massMolar mass Number of moles of oxygen = 1032 = 0
3125Number of moles of nitrogen = 5028 = 1
7857b) As per ideal gas equationpV= nRTp = nRTV  Pressure of oxygen = 0
3125 × 0 0821 × 30010 = 0
7697 atm Pressure of nitrogen = 1
7857 × 0 0821 × 30010 = 4
3982 atmc) Total pressure = Pressure of oxygen +  Pressure of nitrogen = 0
7697 +4 3982  =5 1679 atm

14) A gaseous mixture containing 50 g of nitrogen and 10 g of oxygen were enclosed in a vessel of 10 L capacity at 27 ° C . Calculate : a) the number of moles of each gas b) the partial pressure of each gas c) the total pressure of the gaseous mixture

14) A gaseous mixture containing 50 g of nitrogen and 10 g of oxygen were enclosed in a vessel of 10 L capacity at $27 ° C$ . Calculate :
a) the number of moles of each gas
b) the partial pressure of each gas
c) the total pressure of the gaseous mixture